Question

expand (5x+3)(5x-5)(5x-4)by using identit
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Answer 1

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

expand (5x+3)(5x-5)(5x-4)by using identity

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}$

$\sf\implies(5x+3)(5x-5)(5x-4)$

${\bold{\blue{\boxed{\bf{(x+a)(x+b) = x^2 + x(a+b)+ab }}}}}$

$\sf\implies((5x)^2 + 5x(+3-5)(-5 * 3)(5x-4)$

$\sf\implies(25x^2 + 5x(-2) + (-15))(5x-4)$

$\sf\implies(25x^2 - 10x -15 )(5x-4)$

$\sf\implies 5x(25x^2 - 10x -15 )-4(25x^2 - 10x - 15)$

$\sf\implies 125x^3 - 50x^2 - 75 - 100x^2 + 40x + 60$

$\sf\implies 125x^3 - 150x^2 + 40x - 15$

$\sf\implies 5 (25x^3 - 30x^2 + 8x - 3 )$

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