Question

Expand: (6a- 4b)2

Expand​

Answer 1

$\LARGE\textsf{\underline\textcolor{aqua}{↭ FoRmUla :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{( a - b )² = a² + b² - 2ab}}$

$\large\textsf{ }$

$\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}$

$\large\textsf{ }$

Here,

• a = 6a
• b = 4b

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{( 6a - 4b )² = ( 6a )² + ( 4b )² - 2 ( 6a × 4b )}$

$\qquad\tt{:}\longrightarrow\large\textsf{= 36a² + 16b² - 2 ( 24ab )}$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{= 36a² + 16b² - 48ab}}$

$\large\textsf{ }$

$\LARGE\textsf{\underline\textcolor{aqua}{↭ AlGeBrAiC fOrMuLaS :-}}$

$\large\textsf{ }$

$\boxed{\begin{array}{c }\qquad\tt{:}\longrightarrow\large\textsf{( a + b )² = a² + b² + 2ab}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{( a - b )² = a² + b² - 2ab}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a² - b² = ( a + b ) ( a - b )}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a² + b² = ( a + b )² - 2ab}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a³ + b³ = ( a + b ) ( a² - 2ab + b² )}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a³ - b³ = ( a - b ) ( a² + ab + b² )}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac }\end{array}}$

Answer 2

Answer:

(6a-4b)²= [( a-b)²= a²-2ab+b²]

So (6a-4b)²= (6a)²-2×6a×4b+ (4b)²

=36a²- 48ab+ 16b²