Question

expand (a+2b-3c)^2 please answer this question
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Answer 1

$\huge{\mathbb{\pink{\fcolorbox{pink}{gold}{†AnSwEr†}}}}$

$\implies( a + 2b - 3c )²$

$\implies( a + 2 × b - 3 × c )²$

$\implies a² + 2² × b² - 3² × c²$

$\implies a × a + 2 × 2 × b × b - 3 × 3 × c × c$

HØPÈ ÏT HÊLPS ♠♦♠

Answer 2

Given :-

$\sf {(a + 2b - 3c)}^{2}$

To,

Expand

Solution :-

$\sf {(a)}^{2} + {(2b)}^{2} + {( - 3c)}^{2} + 2(a)(2b) + 2(2b)( - 3c) + 2( - 3c)(a)$

$\sf {a}^{2} + {4b}^{2} + {9c}^{2} + 4ab - 12bc - 3ca$

Procedure :-

→ This question is from the Algebraic identites.

→ This is question we have to expand the given expression. By Using 5th identity of Algerbric identites, we will solve this expression.

→ First we will multiply the constants which are in the brackets and after that we will multiply it with the 2 which is outside the bracket.

→ We have out a negetive sign too, because (+)(-) = -. Hence the final answer is a² + 4b² + 9c² + 4ab-12bc-3ca

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