Expand : (-a - b/3 + 3c)²
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Step-by-step explanation:
(a−2b−3c)2
According to the equation ,
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
So we get,
Using the formula we can it write it as
(a−2b−3c)2=a2+(−2b)2+(−3c)2+2a(−2b)+(2(−2b)(−3c)+2(−3c)a
On further calculation we get,
(a−2b−3c)2=a2+4b2+9c2−4ab+12bc−6ac
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