Math, asked by sathiyabama, 1 year ago

expand a-b+c whole square


umasubafs: The square of the sum of three or more terms can be determined by the formula of the determination of the square of sum of two terms.

Now we will learn to expand the square of a trinomial (a + b + c).

Let (b + c) = x

Then (a + b + c)2 = (a + x)2 = a2 + 2ax + x2

= a2 + 2a (b + c) + (b + c)2

= a2 + 2ab + 2ac + (b2 + c2 + 2bc)

= a2 + b2 + c2 + 2ab + 2bc + 2ca

Therefore, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
sathiyabama: I can't understand

Answers

Answered by umasubafs
2

The square of the sum of three or more terms can be determined by the formula of the determination of the square of sum of two terms.

Now we will learn to expand the square of a trinomial (a + b + c).

Let (b + c) = x      

Then (a + b + c)2 = (a + x)2 = a2 + 2ax + x2

                        = a2 + 2a (b + c) + (b + c)2  

                        = a2 + 2ab + 2ac + (b2 + c2 + 2bc)  

                        = a2 + b2 + c2 + 2ab + 2bc + 2ca

Therefore, (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

Answered by koustubhi2604
0

(a + b + c)³ = a³ + b³ + c³ + 3 (a +b) (b + c) (a+ c)

Proof:

(a + b + c)³ = a³ + b³ + c³ + 3 (a +b) (b + c) (a+ c).


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