Math, asked by shubham5616, 1 year ago

expand by using identity (2x - y + z)^2

Answers

Answered by gaurav2013c
16

 {(2x - y + z)}^{2}  \\  \\  =  {(2x)}^{2}  +  {( - y)}^{2}  +  {(z)}^{2}  + 2(2x)( - y) + 2( - y)(z) + 2(z)(2x) \\  \\  = 4 {x}^{2}  +  {y}^{2}  +  {z}^{2}  - 4xy - 2yz + 4zx
Answered by MarkAsBrainliest
12
\bold{Answer :}

We know that,

(a + b + c)²

= a² + b² + c² + 2ab + 2bc + 2ca

Now,

(2x - y + z)²

= {2x + (- y) + z}²

= (2x)² + (- y)² + (z)² + {2 × 2x × (- y)} + (2 × 2x × z) + {2 × (- y) × z}

= 4x² + y² + z² - 4xy + 4xz - 2yz,

which is the required expansion.

#\bold{MarkAsBrainliest}
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