Question

expand each of the following using suitable identities (2x-y+z)^2​

Answer 1

Step-by-step explanation:

(2x-y+z)²

={(2x)² + (-y)² + (z)² + 2(2x)(-y)+2(-y)(z)+2(z)(2x)}

={4x²+y²+z² - 4xy - 2yz + 4zx}

By using (a+b+c)=a²+b²+c²+2ab+2bc+2ca

*Hope this will help you. plz thank me.

Answer 2

$\huge\bold\red{Answer}$

$\bf \: (2x - y + z)^{2}$

$\bf \: By \: using \: Identity:-$

$\bf \: (x + y + z) ^{2} = {x}^{2} + {y}^{2} + {z}^{2} + \: 2xy \: + \: 2yz \: + 2zx \: \:$

$\bf\: (2x \: + ( \: - y) \: + z) ^{2} = {x}^{2} \: + {y}^{2} \: + {z}^{2} \: + 2 \times 2x \: ( - y) \: + 2 \: \times \: \: ( \: - y) \: \times z \: \: + \: 2 \: \times \: z \: \times \: x$

$\bf(2x - y + z)^2 =$ $\bf\: \: {4x}^{2} \: + \: {y}^{2} \: + \: {z}^{2} - 4xy \: - 2yz \: + \: 2zy \:$