Question

Expand:
$(i) (4x + 3)^{2}$ $(ii) (x + 2y)^{2}$ $(iii) (x + \frac{1}{x} )^{2}$$(iv) (x-\frac{1}{x} } )^{2}$

Answer 1

Answer:

Step-by-step explanation:

(1) (4x+3)² = (4x) ² + (3)² + 2×4x×3

= 16x² + 9 + 24x

(2). (x+2y) ² = x² + 4y² + 4xy

(3). (x + (1/x)) ² = x² + (1/x) ² + 2

(4). (x-(1/x)) ² = x² + (1/x) ² - 2

HOPE IT HELPS YOU ♥️♥️

Answer 2

Hii dear here is your answer.....

This answer is verified ✅✅

$a) \: {(4x + 3)}^{2}$

Using the formula......
${( {a} + {b})}^{2} = {a}^{2} + {b}^{2} + 2ab$

Put in formula......

$= {(4x)}^{2} + {(3)}^{2} + 2 \times 4x \times 3$

$= 16 {x}^{2} + 9 + 24x$

b)
${(x + 2y)}^{2}$

Put in formula........
$= {(x)}^{2} + {(2y)}^{2} + 2 \times x \times 2y$
$= {x}^{2} + 4 {y}^{2} + 4xy$

c)
${ (x + \frac{1}{x}) }^{2}$

Put in formula.....

${(x)}^{2} + \frac{1}{ {(x)}^{2} } + 2 \times x \times \frac{1}{x}$

${x}^{2} + \frac{1}{ {x}^{2} } + 2$

d)
${(x - \frac{1}{x} ) }^{2}$

Put in formula.....

${( {x)}^{2} + \frac{1}{(x)} }^{2} - 2 \times x \times \frac{1}{x}$

${x}^{2} + \frac{1}{ {x}^{2} } - 2$

Hope it will help you.......



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