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Given:
- Square of a Irrational number is given to us.
To Find:
- The expanded value of the number.
Concept Used:
- We will use the formula of (a+b)².
Answer:
Here its given square of a irrational number which is (√3+1)².
We will be using
- ☞ (a+b)²=a²+b²+2ab.
Using above identity ,
= (√3+1)²
=(√3)²+(1)²+2×1×√3.
=3+1 +2√3 .
=4+2√3.
Hence the expanded value is 4+2√3.
Some more identities:
☞(a+b)²=a²+b²+2ab = (a-b)²+4ab.
☞(a-b)²=a²+b²-2ab =(a+b)²-4ab.
☞a²-b²=(a+b)(a-b)
☞(a-b)³= a³-b³-3ab(a-b)
☞(a+b)³= a³+b³+3ab(a+b)
☞a³+b³=(a+b)(a²-ab+b²)
☞a³-b³=(a-b)(a²+ab+b²)
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