expand the cube [3/2x + 1]^3
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(3/2x + 1)³ = (3/2x)³ + (1)³ + 3(3/2x)³(1) + (3/2x + 1)
=27/8x³ + 1 + 27/4x² + 9/2x
= 27/8x³ + 27/4x² + 9/2x + 1
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Answer:
Step-by-step explanation:
[ 3/2 x + 1] ^3 = [ 3/2 x]^3 + (1)^3 +
= 27/8 x^3 + 1 + 9/2x ( 3/2x + 1 )
= 27/8 x^3 +1 + 27/4^x ^2 +9/2 x
= 27x^3 + 27/4x^2 + 9/2x +1
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