how many different (non-congruent) triangles can you draw with two sides 8and6centimeters and area 12 Square centimetres ?what if the area is to be 24 square centimetres?
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hlo mate here is ur ans........
Area of a triangle = 1/2.a.c.sinB
12 cm^2= 1/2.8 cm.6 cm.sinB.
or. sinB=12/24 = 1/2
or. B= 30° or 150°.
Thus , only two triangles are possible to draw.
(1) sides a=8 cm , c=6 cm and angle between them B=30°.
(2)sides a=8 cm , c=6 cm and angle between them B=150°. Answer.
Again , area of the triangle = 1/2.a.c.sinB
24 cm^2= 1/2.8 cm.6 cm.sinB
24 = 24.sinB
or. sinB=24/24= 1
or B= 90°.
Thus , only a right angled triangle in which a=8 cm ,c =6 cm and
angle between them B= 90°. Answer.....
hope this hepls uh dear....
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