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(x-1/x+3)(x+1/x+3)
=(x)^2-[(1/x+3)^2]
=x^2-[1/x^2+6/x+9]
=x^2-1/x^2-6/x-9
=x^3-1/x-6-9x
=(x)^2-[(1/x+3)^2]
=x^2-[1/x^2+6/x+9]
=x^2-1/x^2-6/x-9
=x^3-1/x-6-9x
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