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(2a-3b+4c)^2
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Answer:
the answer is 4a^2+9b^2+16c^2 -12ab -24bc +16ca
Step-by-step explanation:
formula is (a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca
here
a=2a
b=-3b
c=4c
(2a-3b+4c)^2 = (2a)^2+(-3b)^2+(4c)^2 +2(2a)(-3b)+2(-3b)(4c)+2(4c)(2a)
= 4a^2+9b^2+16c^2 -12ab -24bc +16ca
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