Math, asked by Urmomisawhore, 11 months ago

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(2a-3b+4c)^2

Answers

Answered by kesavan6174
2

Answer:

the answer is 4a^2+9b^2+16c^2 -12ab -24bc +16ca

Step-by-step explanation:

formula is (a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca

here

a=2a

b=-3b

c=4c

(2a-3b+4c)^2 = (2a)^2+(-3b)^2+(4c)^2 +2(2a)(-3b)+2(-3b)(4c)+2(4c)(2a)

= 4a^2+9b^2+16c^2 -12ab -24bc +16ca

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