Question

Expand the following: (2ab + 3cd)²​

Answer 1

Answer:

We know that:

$(x+y)²=x²+2xy+y²$

So after expanding (2ab + 3cd)² the result will be:

${(2ab + 3cd)}^{2} \\ = ({2ab})^{2} + 2 \times 2ab \times 3cd + ({3cd})^{2} \\ = ({4ab})^{2} + 12abcd + ({9cd})^{2}$

Answer 2

Step-by-step explanation:

64+48cd+9c²d²

opppppp