Question

expand the following (2x + 1/3x ) ^ 2​

Answer 1

Answer:

$\huge\colorbox{yellow}{Answer\:-}$

${(2x + \frac{1}{3}x) }^{2}$

Now,

${(2x + \frac{1}{3}x) }^{2}$

$= {(2x + \frac{1x}{3}) }^{2}$

$= {(2x + \frac{x}{3} )}^{2}$

$= (2x + \frac{x}{3})(2x + \frac{x}{3})$

$= 2x(2x + \frac{x}{3}) + (2x + \frac{x}{3}). \frac{x}{3}$

$= {4x}^{2} + 2x. \frac{x}{3} + (2x + \frac{x}{3}) . \frac{x}{3}$

$= {4x}^{2} + \frac{2xx}{3} + (2x + \frac{x}{3}). \frac{x}{3}$

$= {4x}^{2} + \frac{ {2x}^{2} }{3} + (2x + \frac{x}{3}). \frac{x}{3}$

$= {4x}^{2} + \frac{ {2x}^{2} }{3} + \frac{(2x + \frac{x}{3}).x }{3}$

$= {4x}^{2} + \frac{ {2x}^{2} }{3} + \frac{ {2x}^{2} + x. \frac{x}{3} }{3}$

$= {4x}^{2} + \frac{ {2x}^{2} }{3} + \frac{ {2x}^{2} + \frac{xx}{3} }{3}$

$= {4x}^{2} + \frac{ {2x}^{2} }{3} + \frac{ {2x}^{2} + \frac{ {x}^{2} }{3} }{3}$

$\pink{ = > {4x}^{2} + \frac{ {2x}^{2} }{3} + \frac{ {2x}^{2} + \frac{ {x}^{2} }{3} }{3} }$

$\huge\colorbox{yellow}{Thank\:You}$

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Answer 2

Answer:

expand the following (2x + 1/3x ) ^ 2