Question

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Answer 1

Answer:

1. The impulse imparted to the mass is 0.5 kg-m/s.

It is given that,

Mass of the object, m = 3 kg

Force acting on the object, F = 5 N

Time of contact, t = 0.1 s

Let J is the impulse imparted to mass. It is equal to the product of force and time of contact. It is given by :

J=F×t

J=5 N×0.1 s

J = 0.5 kg-m/s

So, the impulse imparted to the mass is 0.5 kg-m/s. Hence, this is the required solution.

2. From Newton's second law of motion, the applied force is directly proportional to the acceleration produced or F=ma

The unit of force is newton in SI denoted by the  symbol  N.

Forces acting on a mass m  1  with acceleration a  1  and mass m  2  with acceleration a  2  are as given below.

m  1  = F/a  1  = 5/8 kg

m  2  =  F / a 2 = 5/24 kg

M=(  5/8 +5/24 ) kg = ( 5/6 )kg

Acceleration produced in M (when the two masses are tied together),

a=  F /M =5/5/6 =6 ms^-2.  

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