Question

Expand the following (4a – 2b - 3c)²

Answer 1

Step-by-step explanation:

(4a−2b−3c)²

=(4a+−2b+−3c)(4a+−2b+−3c)

=(4a)(4a)+(4a)(−2b)+(4a)(−3c)+(−2b)(4a)+(−2b)(−2b)+(−2b)(−3c)+(−3c)(4a)+(−3c)(−2b)+(−3c)(−3c)

=16a²−8ab−12ac−8ab+4b²+6bc−12ac+6bc+9c2²

=16a²−16ab−24ac+4b²+12bc+9c²

Answer 2

Answer:

first u should read the formula....then u can easily expand.....

use the formula :(a+b+c)2 or (a-b-c)2

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

in this way u expand the sum by keeping minus symbol...sorry i cant do it right now but hope it helps...if u have more doubt ask this ques at tmrr 9:00

i will ans this...plz follow me...and thank.my ans