Question

EXPAND THE FOLLOWING WITH STEPS:
        a) {x/7 -y/a}square
         b) {9+1/3a}square

Answer 1

$Use:(a\pm b)^2=a^2\pm2ab+b^2\\\\\\a)\ \left(\frac{x}{7}-\frac{y}{a}\right)^2=\left(\frac{xa}{7a}-\frac{7y}{7a}\right)^2=\left(\frac{ax-7y}{7a}\right)^2=\frac{(ax-7y)^2}{(7a)^2}\\\\=\frac{(ax)^2-2(ax)(7y)+(7y)^2}{49a^2}=\frac{a^2x^2-14axy+49y^2}{49a^2}$


$b)\ \left(9+\frac{1}{3}a\right)^2=9^2+2(9)(\frac{1}{3}a)+\left(\frac{1}{3}a\right)^2=81+6a+\frac{1}{9}a^2$

Answer 2

Answer:

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