Question

Expand the given value (2x–2/x)³​

Answer 1

Answer:

Please see the attached document for the answer...

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Answer 2

The correct answer is $8x^{3}-\frac{8}{x^{3} } -24x+\frac{24}{x}$.

Given: The equation = $(2x-\frac{2}{x} )^{3}$.

To Find: Expand the term.

Solution:

The identity: $(a-b )^{3} =a^{3} -b^{3}-3ab(a-b)$.

$(2x-\frac{2}{x} )^{3}$ = $(2x)^{3} -(\frac{2}{x} )^{3} -3*2x*\frac{2}{x} (2x-\frac{2}{x} )$

=  $8x^{3}-\frac{8}{x^{3} } -12(2x-\frac{2}{x} )$

=  $8x^{3}-\frac{8}{x^{3} } -24x+\frac{24}{x}$

Hence, the expansion of  $(2x-\frac{2}{x} )^{3}$ is  $8x^{3}-\frac{8}{x^{3} } -24x+\frac{24}{x}$.

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