Question

expand the identity (x-y)cube​

Answer 1

Answer:

$\geqslant x ^{3} - 3x ^{2}y + 3xy^{2} - y ^{3}$

Step-by-step explanation:

Solution:-

$\geqslant \geqslant \geqslant a {}^{3} + 3a^{2}b + 3ab ^{2} + b^{3}$

$x^3+3(x)^2(-y)+3x(-y)^2+(-y)^3$

$\geqslant x ^{3} - 3x ^{2}y + 3xy^{2} - y ^{3}$