Expand using identities(3x+4z) ³
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first of all (a+b)cube= a cube +3a cube b + 3ab cube + b cube
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Answer:
Step-by-step explanation:
(3X+4z)³
Using identity (a+b)³= a³+b³+3X²y+3Xy²
=(3X)³+(4z)³+3×(3X)²×4z+3×3X×(4z)²
27X³+64z³+3×9X²×4z+3×3X×16z²
27X³+64z³+108X²z+144Xz²
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