Expand using Identities (i) (x+2y)3
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(x + 2y)³
Using identity
(a+b)³ = a³ + b³ + 3ab(a+b)
we get,
x³ + (2y)³ + 3×x×2y(x+2y)
x³ + 8y³ + 6xy(x+2y)
x³ + 8y³ + 6x²y + 12xy² ..ans....
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