Question

Expand using Identities (i) (x+2y)3

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Answer 1

(x + 2y)³

Using identity

(a+b)³ = a³ + b³ + 3ab(a+b)

we get,

x³ + (2y)³ + 3×x×2y(x+2y)

x³ + 8y³ + 6xy(x+2y)

x³ + 8y³ + 6x²y + 12xy² ..ans....

Answer 2

Answer:

${(x + 2y)}^{3}$

$= {x}^{3} + {(2y)}^{3} + 3(x)(2y)(x + 2y)$

$= {x}^{3} + 8 {y}^{3} + 6xy(x + 2y)$

$= {x}^{3} + 8 {y}^{3} + 6 {x}^{2} y + 12x {y}^{2}$

$By \: using \: the \: identity, \:$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)$