Expand using identity (x-y+3z)square whole square pls answer
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Answer:
(x-y+3z)²
Ans.
Identity used=(a+b+c)²=a²+b²+c²+2ab+2bc+2ac
Then,
(x-y+3z)²=(x)²+(-y)²+(3z)²+2×x×-y+2×-y×3z+2×3z×x
=x²+y²+9z²-2xy-6yz+6xz
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