Question

expand using suitable identities (3/2x-1)^3


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Answer 1

Answer:

$\left(\frac{3}{2x-1}\right)^3$

=$\frac{3^3}{\left(2x-1\right)^3}$

=$\frac{27}{\left(2x-1\right)^3}$

=$\frac{27}{8x^3-12x^2+6x-1}$

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