Question

find the complement of F=ac+abd+acd​

Answer 1

Answer:

A(B+C)=AB+AC; A+BC=(A+B) ( A+C); (A+B) ( C+D)=AC+AD+BC+BD....+F'.COMPLEMENT OF A BOOLEAN FUNCTION : to compute the.... to get it in POS form apply demograns law twice i.e F' ( A,B,C)

Answer 2

The complement of F=ac+abd+acd​ is F'=(a'+c').(a'+b'+d').(a'+c'+d').

Explanation:

According to the given information, we need to find the complement of a function that is,

F=ac+abd+acd​.

Now, complementing both sides we get,

F'=(ac+abd+acd​)'

Now, we know that, by De Morgan's laws, if (a+b) is a function and this function is taken as complement, then, we get,

(a+b)' = a'.b', that is, the individual elements are complemented and the sign changes to .

Now, applying this in our problem,

F'=(ac+abd+acd​)'

=(ac)'.(abd)'.(acd)'

Now, we know that, by De Morgan's laws, if (a.b) is a function and this function is taken as complement, then, we get,

(a.b)' = a'+b', that is, the individual elements are complemented and the sign changes to +

Then, applying this in our problem, we get,

(ac)'.(abd)'.(acd)'

=(a'+c').(a'+b'+d').(a'+c'+d')

Thus, the complement of F=ac+abd+acd​ is F'=(a'+c').(a'+b'+d').(a'+c'+d').

Learn more here

https://brainly.in/question/13402384

Learn more

https://brainly.in/question/19026399