Expand using suitable identities (3x-2y+5z)^2
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Answered by
37
(3x-2y+5z)^2
=(3x)^2+(2y)^2+(5z)^2+2(3x)(-2y)+2(-2y)(5z)+2(5z)(3x)
=9x^2+4y^2+25z^2-12xy-20yz+30zx
=(3x)^2+(2y)^2+(5z)^2+2(3x)(-2y)+2(-2y)(5z)+2(5z)(3x)
=9x^2+4y^2+25z^2-12xy-20yz+30zx
Rythm14:
thank you
Answered by
48
Hello mate!!!!!
Here is your solution....
(3x - 2y + 5z) ^2
Using identity = (x+y+z)^2 = (x^2+y^2+ z^2 + 2xy + 2yz + 2zx)
= ((3x)^2 + (-2y)^2 + (5z)^2 + 2×3x×-2y + 2×-2y×5z + 2×5z×3x)
= (9x^2 +4y^2 +25z^2 -12xy -20yz +30xz)
HOPE THIS WILL HELP YOU....
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