expand using suitable identities (x-2/3y)^3
Answers
Answered by
77
(a-b)³ = a³- b³ - 3ab(a-b)
[(x-2)/3y]³
=(x-2)³/(3y)³
= x³ - 8 - 6x(x-2) / 27y³
[(x-2)/3y]³
=(x-2)³/(3y)³
= x³ - 8 - 6x(x-2) / 27y³
Hiteshbehera74:
thanks
Answered by
82
Hi ,
******************************************
We know the identity ,
( a - b )³ = a³ - 3a²b + 3ab² - b³
*****************************************
Here ,
(x-2/3y)³=x³-3x²(2y/3 )+3x(2y/3)²-(2y/3)³
= x³ - 2x²y + 4y²/3 - 8y³/27
I hope this helps you.
: )
******************************************
We know the identity ,
( a - b )³ = a³ - 3a²b + 3ab² - b³
*****************************************
Here ,
(x-2/3y)³=x³-3x²(2y/3 )+3x(2y/3)²-(2y/3)³
= x³ - 2x²y + 4y²/3 - 8y³/27
I hope this helps you.
: )
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