Question

Expand using suitable identity
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( √2x + 2y - √3z ) square ( rase to the power 2 ) ​

Answer 1

Step-by-step explanation:

${( \sqrt{2}x + 2y - \sqrt{3}z)}^{2} = \\ {( \sqrt{2}x})^{2} + {(2y)}^{2} + {( \sqrt{3}z)}^{2} \\ + 2( \sqrt{2}x)( 2y) - 2(2y)(\sqrt{3}z) \\ - 2( \sqrt{3}z)( \sqrt{2}x) \\=2{x}^{2} + 4 {y}^{2} + 3 {z}^{2} \\ + 4 \sqrt{2}xy - 4 \sqrt{3}yz - 2 \sqrt{6}zx$

${(a + b - c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab - 2bc - 2ca$