Expand using suitable identity: (2x – 5y) (2x – 5y).
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Answered by
6
Heya user !!!
Here's the answer you are looking for
(2x – 5y) (2x – 5y)
= (2x - 5y)²
We know (a - b)² = a² - 2ab + b²
So,
(2x – 5y) (2x – 5y)
= (2x - 5y)²
= (2x)² - 2(2x)(5y) + (5y)²
= 4x² - 20xy + 25y²
Therefore, the expansion for (2x – 5y) (2x – 5y) is 4x² - 20xy + 25y².
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
(2x – 5y) (2x – 5y)
= (2x - 5y)²
We know (a - b)² = a² - 2ab + b²
So,
(2x – 5y) (2x – 5y)
= (2x - 5y)²
= (2x)² - 2(2x)(5y) + (5y)²
= 4x² - 20xy + 25y²
Therefore, the expansion for (2x – 5y) (2x – 5y) is 4x² - 20xy + 25y².
★★ HOPE THAT HELPS ☺️ ★★
kannaburramukkoxx400:
thanks
Answered by
3
Hi !
(2x – 5y) (2x – 5y) = (2x - 5y)²
We know that ,
(a - b)² = a² - 2ab + b²
So,
=> (2x - 5y)²
=> (2x)² - 2*2x*5y* + (5y)²
=> 4x² - 20xy + 25y²
(2x – 5y) (2x – 5y) = 4x² - 20xy + 25y².
(2x – 5y) (2x – 5y) = (2x - 5y)²
We know that ,
(a - b)² = a² - 2ab + b²
So,
=> (2x - 5y)²
=> (2x)² - 2*2x*5y* + (5y)²
=> 4x² - 20xy + 25y²
(2x – 5y) (2x – 5y) = 4x² - 20xy + 25y².
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