find the value of x,y,z
Attachments:
raju65:
Is it possible to have a triangle in which (a)each angle is equal to 45degree (b)two of the angles are right angles (c) each angle is equal to
Answers
Answered by
2
In the uppermost triangle
25°+75°+x=180(angle sum property)
100+x=180
x =180-100
x= 80°
###... angle 25°=angle y(corresponding angles)
y=25
75+z= 180(linear pair
z=180-75
z=105.....(this is because of linear pair the angle adjacent to 75 will be 180-75 and tha angle will equal to z because of corresponding angles property)
In second figure in the triangle the third angle will be 35(alternate angles)
x+35+53=180(angle sum property)
88+x=180
x=180-88
x=92
Hope it helped....
25°+75°+x=180(angle sum property)
100+x=180
x =180-100
x= 80°
###... angle 25°=angle y(corresponding angles)
y=25
75+z= 180(linear pair
z=180-75
z=105.....(this is because of linear pair the angle adjacent to 75 will be 180-75 and tha angle will equal to z because of corresponding angles property)
In second figure in the triangle the third angle will be 35(alternate angles)
x+35+53=180(angle sum property)
88+x=180
x=180-88
x=92
Hope it helped....
Answered by
1
Hi !
In the triangle , that contains angle "x"
by angle sum property ,
75° + 25° + x° = 180°
100 + x° = 180°
∠ x = 80°
the angle above ∠ z = 75°( corresponding angles)
but ,
we know that
∠z + 75 = 180° ( linear pair)
z = 180 - 75
∠z = 105°
I have attached the same figure , in this ans with labellings.
in the figure ,
∠PAQ = 25° (Vertically opposite angles )
Also,
∠PAQ = ∠y ( alternate interior angles)
∴ ∠y = 25°
In the triangle , that contains angle "x"
by angle sum property ,
75° + 25° + x° = 180°
100 + x° = 180°
∠ x = 80°
the angle above ∠ z = 75°( corresponding angles)
but ,
we know that
∠z + 75 = 180° ( linear pair)
z = 180 - 75
∠z = 105°
I have attached the same figure , in this ans with labellings.
in the figure ,
∠PAQ = 25° (Vertically opposite angles )
Also,
∠PAQ = ∠y ( alternate interior angles)
∴ ∠y = 25°
Attachments:
Similar questions