Expand using suitable identity (-4x + 2y - 2)^2
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Answer:
16x²+4y²-4+2(-8xy-4y+8x)
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identity to be used is:-
(a + b + c )^2 = a^2 + b^2 + c^2 + 2( ab + bc + ca)
now,
(- 4x + 2y - 2 )^2 =
(-4x)^2 + (2y)^2 + (-2)^2 + 2[ ( -4x × 2y) + ( 2y × -2) + ( -2 × -4x) ]
16 x^2 + 4y^2 + 4 + 2 [ -8xy - 4y + 8x ]
16 x^2 + 4y^2 + 4 - 16xy - 8y + 16x
4 [ 4x^2 + y^2 + 1 - 4xy - 2y + 4x].
hope this helps you...!!
#BAL
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