expand using suitable identity(x+2y+4z)²
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- Answer -
→ (x + 2y + 4z)²
→ (x)² + (2y)² + (4z)² + 2 × x × 2y + 2 × 2y × 4z + 2 × x × 4z
→ x² + 4y² + 16z² + 4xy + 16yz + 8xz
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Step-by-step explanation:
(x+2y+4z)²
=(x)²+(2y)²+ (4z)²+2×x×2y+2×2y×4z+2×4z×x
=x²+4y²+16z²+4xy+16yz+8xz
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
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