Question

expand - X + 2 Y - 3 Z whole square​

Answer 1

$\huge\mathcal{Heya!}$

$<b>$

Using the identity :

(a+b+c)^2

= a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

Refer to the attachment

Hope this helps dear!!❤️

Answer 2

Answer:

Using (a+b×c)^2 identity, we can make it in the form of a^2+b^2+c^2+2ab+2bc+2ca

here

a=-x

b=2y

c=-3z

this implies

x^2+4y^2+9z^-4xy-12yz+6zx

please mark brainliest

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