Math, asked by kishoredhakshi, 8 months ago

Expand ( x-2y/3)cube using suitable identities

Answers

Answered by abhishekc133
3

Answer:

x^3-2x^2y-+4xy^2/3-8y^3/27

Step-by-step explanation:

(x-2y/3)^3

=x^3-3x^2.2y/3+3.x.(2y/3)^2-(2y/3)^3

=x^3-2x^2y+4xy^2/3-8y3/27

Similar questions