Expand ( x-2y/3)cube using suitable identities
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Answer:
x^3-2x^2y-+4xy^2/3-8y^3/27
Step-by-step explanation:
(x-2y/3)^3
=x^3-3x^2.2y/3+3.x.(2y/3)^2-(2y/3)^3
=x^3-2x^2y+4xy^2/3-8y3/27
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