Question

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(x+2y+4z)^2

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Hey!! Here is your Answer...

(x + 2y + 4z)2

Identity V : (x + y + z)2= x2+ y2+ z2+ 2xy + 2yz + 2zx

here, x = x ; y = 2y ; z = 4z

= x2 + (2y)2 + (4z)2 + 2(x)(2y) + 2(2y)(4z) + 2(4z)(x)

= x2 + 4y2 + 4z2 + 4xy + 16yz + 8xz

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