expand (x +3 )^3
please help
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Answered by
4
HEYA MATE !
(a+b)³=a³+b³+3ab(a+b)
(x+3)³=x³+27+3(x)(3)(x+3)
=x³+27+9x(X+3)
=x³+27+9x²+27
=x³+9x²+54
hope it helps
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Anonymous:
nice
Answered by
1
=X^3 +3^3 + 3×X×3 ( X +3 ) {Using identity :- (a+b)^3 = a^3 + b^3 + 3ab( a+b )}
=X^3 + 27 + 9X (X +3)
=X^3 + 27 + 9X^2 + 27
=X^3 + 54 + 9X ^2
=X^3 + 9X^2 + 54
I hope this answers your question.
=X^3 + 27 + 9X (X +3)
=X^3 + 27 + 9X^2 + 27
=X^3 + 54 + 9X ^2
=X^3 + 9X^2 + 54
I hope this answers your question.
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