Question

expand (x+y-z)^2 solve ​

Answer 1

Answer:

(x+y−z)

(x+y−z) 2

(x+y−z) 2 =x

(x+y−z) 2 =x 2

(x+y−z) 2 =x 2 +y

(x+y−z) 2 =x 2 +y 2

(x+y−z) 2 =x 2 +y 2 +z

(x+y−z) 2 =x 2 +y 2 +z 2

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z)

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x 2

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x 2 +y

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x 2 +y 2

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x 2 +y 2 +z

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x 2 +y 2 +z 2

(x+y−z) 2 =x 2 +y 2 +z 2 +2(x)(y)−2(y)(z)−2(z)(x)(x+y−z) 2 =x 2 +y 2 +z 2 +2xy−2yz−2zx

Answer 2

Answer:

x^2+y^2+z^2+2xy-2yz-2za