Question

expanf the following using suitable identities (4-1/3x)^3​

Answer 1

Answer:

$( {4 - \frac{1}{3x} })^{3}$

${(a - b)}^{3} = {a}^{3} + {b}^{3} - 3ab(a - b)$

$( {4 - \frac{1}{3x} })^{3} = {4}^{3} + ({ \frac{1}{3x} }^{3} ) - 3 \times 4 \times \frac{1}{3x} (4 - \frac{1}{3x} )$

=64+1/9x^3-4/x(4-1/3x)