Math, asked by divyeshp9438, 3 months ago

Expansion of (4-p)³ =4³ - [.....] + 12p² - p³

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Answered by kumarsantosh04984
1

Answer:

(4 – p)³ = (4)³ – 3(4)²(p) + 3(4)(p)² – (p)³ … [(a – b)³ = a³ – 3a²b + 3ab² – b³] = 64 – 3(16 )(p) + 3(4)(p²) – p³ = 64 – 48p + 12p² – p³. iii. Here ...

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