expansion of identity (x+y+z)²is
Answers
Answered by
3
Answer:
(x-y-z)² = x²+y²+z²-2xy+2yz-2zx
Step-by-step explanation:
(x-y-z)²
= [x+(-y)+(-z)]²
= x²+(-y)²+(-z)²+2x(-y)+2(-y)(-z)+2(-z)x
/* By algebraic identity:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca */
= x²+y²+z²-2xy+2yz-2zx
Therefore,
(x-y-z)² = x²+y²+z²-2xy+2yz-2zx
•••♪
Answered by
4
(x-y-z)² = x²+y²+z²-2xy+2yz-2zx
Step-by-step explanation:
(x-y-z)²
= [x+(-y)+(-z)]²
= x²+(-y)²+(-z)²+2x(-y)+2(-y)(-z)+2(-z)x
/* By algebraic identity:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca */
= x²+y²+z²-2xy+2yz-2zx
Therefore,
(x-y-z)² = x²+y²+z²-2xy+2yz-2zx
hope it helps u
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