Question

expansion of identity (x+y+z)²is​

Answer 1

Answer:

(x-y-z)² = x²+y²+z²-2xy+2yz-2zx

Step-by-step explanation:

(x-y-z)²

= [x+(-y)+(-z)]²

= x²+(-y)²+(-z)²+2x(-y)+2(-y)(-z)+2(-z)x

/* By algebraic identity:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca */

= x²+y²+z²-2xy+2yz-2zx

Therefore,

(x-y-z)² = x²+y²+z²-2xy+2yz-2zx

•••♪

Answer 2

(x-y-z)² = x²+y²+z²-2xy+2yz-2zx

Step-by-step explanation:

(x-y-z)²

= [x+(-y)+(-z)]²

= x²+(-y)²+(-z)²+2x(-y)+2(-y)(-z)+2(-z)x

/* By algebraic identity:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca */

= x²+y²+z²-2xy+2yz-2zx

Therefore,

(x-y-z)² = x²+y²+z²-2xy+2yz-2zx

hope it helps u

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