Question

expansion . Please answer me fast please​

Answer 1

Step-by-step explanation:

(2x+3y+4z)(4x^2+9y^2 + 16z^2-6xy-12yz-8zx)

=(2x+3y+4z)^2

its an identity

(x+y+z)^2=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

here in place of x substitute 2x

in place of y substitute 3y and

in place of z substitute 4z

So final answer is

(2x+3y+4z)(4x^2+9y^2 + 16z^2-6xy-12yz-8zx)

=(2x+3y+4z)^2