Explain 2nd part of this question pl
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Explanation:
The object is thrown up, so we need to find out the time in which it reaches the top
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Answer:
u= 0,as it was in rest
v=14m/a,that solved in (1)
The third law of motion is
v=u+at
here a will be g because it is thrown upward
v=u-gt
because the object is thrown against the gravity
now putting the values
0=14-9.8×t
t=1.43s
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