Question

explain and i will mark u brainlist​

Answer 1

$\pink{\bold{\underline{\underline{Answer}}}}$

equation of ellipse 

Focus (+1,−1)

line → x −1=3

e=1/2

→Given focus

(1, - 1) & equation x - y = 3 

SP = e.PM 

$\sf \blue \therefore \green{ {SP}^{2} = {e}^{2} {PM}^{2} }$

$\sf \pink \therefore \purple { {SP}^{2} = \frac{1}{4} {PM}^{2}}$

$\sf \red \therefore \orange{4 {SP}^{2} = {PM}^{2}}$

$\sf \green \implies \blue{4[(x+1 {)}^{2} +(y−1 {)}^{2} ] = ( \frac{x - y - 3}{ \sqrt{ {1}^{2} + (1 {)}^{2} } } {)}^{2} }$

$\sf \purple \implies \pink {4( {x}^{2} + {y}^{2} + 2x - 2y + 2) = (\frac{x - y + 3}{2} {)}^{2} }$

$\sf \orange \therefore \red{8( {x}^{2} + {y}^{2} + 2x - 2y + 2)}$

$\sf \red{= {x}^{2} + {y}^{2} + 9 + 2(x)( - y) + 2( - y)(3) + 2(3x)}$

$\sf \blue \therefore \green{ {7x}^{2} + 2x + {7y}^{2} + 10x - 10y + 7 = 0}$

Answer 2

❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️ ❤️ @ ʜᴇᴀʀᴛᴀᴛᴛᴀᴄᴋᴇʀʙᴀᴄᴄʜɪ ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

❤️❤️❤️❤️❤️❤️Verified Answer :) Purple you Bluestar18❤️❤️❤️❤️❤️

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