Question

) Explain any hoo
practical applications of
heating effect of electric current
An eléctric bulb' is connected to a 220 V
generator if the Cument drawn by the
Bulb is 0.5A then calculate the power of
the bulb.​

Answer 1

Answer:

110 watts

Explanation:

Two applications of heating effect of electric current:

• Oven: oven is an electrical equipment used for heating food and it is used by the principle of heating effect of electric current

• Heater: heater is used for boiling water or producing warm water for bathing purposes and it also works on heating effect of electric current

Voltage or potential difference = 220 volts

Current drawn by the bulb = 0.5 Amperes

Power = V×I

Power = 220×0.5

Power = 110 Watts

110 watts is the power of the bulb

Answer 2

Given:

• Current drawn by the bulb = 0.5 A
• It is connected to a generator that means potential difference = 220V

To find:

• Power of bulb

Solution:

Now, finding power of bulb by

Power = V × I

Where

• V : voltage = 220V
• I : current = 0.5A = ½ A

Substituting the values we have

→ Power = 220 × 1/2

→ Power = 110 Watts

Hence , power of the bulb = 110W