Question

explain balancing of reaction with help of example by hit and trial method..​

Answer 1

Answer:

In this method of balancing chemical equations, trials are made to balance the equation by using the smallest whole number coefficient. Hence, this method is called the hit and trial method.

Explanation:

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Answer 2

Answer:

Let us take a chemical reaction :

$\tt{Fe + H_2O \longrightarrow Fe_3O_4 + H_2}$

We can write the number of Elements in both the sides in this way :

$\boxed{\begin{tabular}{c|c|c}Elements & LHS & RHS\\\cline{1-3}Fe & 1 & 3\\\cline{1-3}H & 2 & 2\\\cline{1-3}O & 1 & 4\end{tabular}}$

Now, We shall start balancing.

Firstly balancing O atoms,

$\tt{Fe + 4H_2O \longrightarrow Fe_3O_4 + H_2}$

Now, balancing H atoms :

$\tt{Fe + 4H_2O \longrightarrow Fe_3O_4 + 4H_2}$

At last, balancing Fe atoms :

$\tt{3Fe + 4H_2O \longrightarrow Fe_3O_4 + 4H_2}$

Hence, the equation is balanced.

Note : Start balancing the Elements which are most imbalanced. In the reaction I took as example, one can see from the table that oxgen was the most imbalanced one. After that, we need to balance the element which gets more unbalanced because of balancing the previous one. And at last, you will be able to balance it.