Question

Rationalise the denomination of 2+3√5 upon 2-3√5 ........ .plzzzz guys give me answer ..if you give me right answer. Then I will send you my Instagram I'd for talking with me ....plzzzz answer my question fast ....

Answer 1

$\huge{\underline{\tt{QUESTION:-}}} \\ \\ Rationalise \: the \: denominator \: \frac{ 2 + 3 \sqrt{5} }{2 - 3 \sqrt{5} } \:? \\ \\ \huge{\underline{\tt{ANSWER:-}}} \\ \\ \frac{2 + 3 \sqrt{5} }{2 - 3 \sqrt{5} } \\ = \frac{2 + 3 \sqrt{5} }{2 - 3 \sqrt{5} } \times \frac{2 + 3 \sqrt{5} }{2 + 3 \sqrt{5 } } \\ = \frac{(2 + 3 \sqrt{5} {)}^{2} }{ ({2})^{2} - (3 { \sqrt{5}) }^{2} } \\ = \frac{ {2}^{2} + 2(2)(3 \sqrt{5} ) + (3 \sqrt{5} {)}^{2} }{4 - (9\times 5)} \\ = \frac{4 + 12 \sqrt{5} + (9 \times 5)}{ 4- 45} \\ = \frac{4 + 12 \sqrt{5} + 45 }{ - 41} \\ = \frac{ - 4 - 12 \sqrt{5} - 45}{41} \\ = \frac{ - 49 - 12 \sqrt{5} }{41}$