Explain bending of a cyclists?
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The torque due to the centripetal force is ( mv2/r BC) which causes an anticlockwise turn that is taken as positive. While negotiating a circular level road of radius r at velocity v, a cyclist has to bend by an angle θ from vertical given by the above expression to stay in equilibrium (i.e. to avoid a fall).
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In order to take a safe turn, the cyclist has to bend a little from his vertical position. In this case, a component of the reaction provides the required centripetal force.
If q is angle made by the cyclist with the vertical then
In actual practice, the value of q is slightly less because the force of friction also contributes towards the centripetal force.
The torque due to the centripetal force is ( mv2/r BC) which causes an anticlockwise turn that is taken as positive. While negotiating a circular level road of radius r at velocity v, a cyclist has to bend by an angle θ from vertical given by the above expression to stay in equilibrium (i.e. to avoid a fall).
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