Chemistry, asked by nick1552, 1 month ago

Explain determination of emf of the cell by potentiometer

Answers

Answered by danielchahar2004
0

Answer:

POTENTIOMETER HAS A WIRE OF SPECIFIC LENGTH WHICH HAS POTENTIAL GRADIENT. THE POINT AT WHICH DEFLECTION IN GALVANOMETER IS ZERO THAT WILL BE THE E.M.F OF SECONDARY CELL ATTACHED TO IT...

Explanation:

Answered by harshiniperiyasami4
0

Answer:

Using a potentiometer, we can determine the emf of a cell by obtaining the balancing length l. Here, the fall of potential along the length l of the potentiometer wire is equal to the emf of the cell, as no current is being drawn from the cell. Then, or, ; where k is the potential gradient along the wire.

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