explain divisibility rule of 11, 4, 6, 7 with two examples to each
Answers
divisibility test for 6
the number should be divisible by both 2 and 3
if the last two digits of a no is divisible by 4 then the no will be dividible by 4
ex 201428 is divisible by 4 because 28 is divisible by 4
if a no is divisible by 2 and 3 then it will be divisible by 6
ex 24444 is divisible by 2 and 3 so it is divisible by 6
to check divisibility by 7 subtract twice the ones digit from the left no if the answer is divisible by 7 then it will be divisible by 7
ex 364=36-2×4
36-8
28which is divisible by 7 so the no. is divisible by 7
to check divisibility by subtract the sum of odd places from even places
ex-165
sum of odd places = 5+1=6
sum of even places= 6
sum of even places-sum of odd places=6-6=0
which is divisible by 11 so the no is divisible by 11