Question

explain hoffmann ammonolysis by giving one example​

Answer 1

Answer:

Hoffmann's ammonolysis : In this reaction alkyl halide is treated with alcoholic ammonia solution to give primary amine

If the alkyl halide is in excess, secondary and tertiary amines are formed:

Tertiary amine further reacts with alkyl halide to form quaternary ammonium salt.

Answer 2

Hoffmann's Ammonolysis is also known as exhaustive ammonolysis of alkyl halide.

Explanation:

First step- Primary amine is a product when alkyl halides are treated with alcoholic ammonia solution.

C₂H₅Br + NH₃→ C₂H₅NH₂+HBr

Bromoethane    Ethyl amine

Second step - Secondary amine and tertiary amines are formed when alkyl halide is in excess

C₂H₅Br + NH₂C₂H₅→ (C₂H₅)₂NH+HBr

Bromoethane           Diethyl amine

(C₂H₅)₂NH + C₂H₅Br→ (C₂H₅)₃N+HBr

Diethyl amine             Tri ethylamine

Third step -tertiary amine further reacts with alkyl halide to form quaternary ammonium salt

C₂H₅Br + (C₂H₅)₃N → [(C₂H₅)₄N]Br

      Tri ethylamine     Tetraethyl ammonium bromide